Abhishek Saini - LinkedIn Creator

Abhishek Saini

Google Software Developer

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Abhishek Saini is a LinkedIn creator based in Bengaluru, Karnataka, India with 124,000 followers, focused on Upskilling, Personal Development, and Coding Tutorials content. Posts average 646 likes and 0.5% engagement.
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My Top Links

Links to my top social media profiles & websites
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Profile Highlights

A quick glance at some key stats
  • 124,000Total Followers
  • 647Avg Likes
  • 9Avg Comments
  • 0.6%Avg Eng.
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Engagement Over Time

Visualization of how my engagement on posts has evolved
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My Activity & Engagement Calendar

Visualizing posting frequency and audience engagement over the last 6 months
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Total posts: 0
Engagement Levels:
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Most Engaged Posts

My Top 3 posts with the highest engagement
Abhishek SainiSWE @Google | Humor and Algorithms | 2200 @Codeforces
New CM of Karnataka has ordered Bangalore Police to remove "Zero Traffic Policy". Because of this policy, whenever any VIP used to come, some roads used to be completely blocked for normal public. I am so happy by this announcement. Now next time, whenever any VIP comes to Bangalore, we don't have to spend 4 hours to travel small distances like 10km. We will only have to spend our usual 3 hours for 10km. Cheers to all of us!
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Abhishek SainiSWE @Google | Humor and Algorithms | 2200 @Codeforces
C++ newbie getting to know about STL
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Abhishek SainiSWE @Google | Humor and Algorithms | 2200 @Codeforces
š—šš—¼š˜ š—œš—»š—±š—¶š—® š—„š—®š—»š—ø šŸ­ š—¶š—» š˜š—µš—² š—Ÿš—²š—²š˜š—°š—¼š—±š—² š—Ŗš—²š—²š—øš—¹š˜† š—–š—¼š—»š˜š—²š˜€š˜ š˜š—¼š—±š—®š˜†. š—Ŗš—¼š—æš—¹š—± š—„š—®š—»š—ø šŸÆšŸ® š—¼š˜‚š˜ š—¼š—³ šŸ®šŸ±,šŸ¬šŸ¬šŸ¬+ š—³š—¼š—¹š—øš˜€. š—Ŗš—®š˜€ š—®š—Æš—¹š—² š˜š—¼ š˜€š—¼š—¹š˜ƒš—² š—®š—¹š—¹ šŸ° š—½š—æš—¼š—Æš—¹š—²š—ŗš˜€ š—¶š—» šŸ®šŸ­ š—ŗš—¶š—»š˜‚š˜š—²š˜€. All Problems Intuitions - Problem A - Check the count of set bits for each number. If equal to the given count, add to the answer. Problem B - If all are selected that case is always counted. Now sort the elements and check before taking 1st, 2nd, and 3rd in that order. The key idea for checking at every stage is last taken (maximum taken) and the next to take (smallest not taken) are the only two elements that matter. Problem C - Calculate the answer for each machine and take the maximum of that. For an answer for a machine, do a binary search on value - what's the maximum number of alloys that can be made within the allowed cost? Problem D - See that all chosen numbers can be perfect squares - 1, 4, 9 like that Now for all other cases, let's say one element is (perfect_square * X), now this X has to be present in all the other chosen numbers too, that's the only way to make the product perfect square. So take all such sets with multiples of above taken perfect squares. For example if X = 2 then 2, 8, 18 like that. If you found this useful, like this to encourage me to write more such educational posts.
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Content Focus

Niche categories & topics I majorly focus on
Upskilling
Personal Development
Coding Tutorials
Career Development
Interview Prep
Tech Trends
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Audience Types

Last Updated At: 05-05-2026
Demographics of my audience & community

Top Role

Software Engineer
Full Stack Engineer
System Engineer
Data Engineer
Founder

Top Locations

Greater Bengaluru Area
Greater Delhi Area
Greater Hyderabad Area
Mumbai Metropolitan Region
Noida

Top Seniority

Entry
Senior
Training
Manager
Owner

Frequently Asked Questions

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